智能家庭中一种基于本体的机器人服务认知机制

doi:10.6040/j.issn.1672-3961.0.2018.495

摘要/Abstract

摘要：

为增强机器人提供不同类型服务的能力,针对智能家庭环境中的服务机器人提出一种基于语义网规则语言的机器人分类服务推理方法。利用本体技术建立智能家庭的本体模型,通过该模型集成来自不同数据源的数据,消除设备之间的异构性。根据智能家庭机器人服务系统的服务特点划分服务类型,利用历史上下文信息生成服务规则库。通过推理引擎匹配实时的上下文信息与服务规则实现机器人的服务推理。智能家庭背景下的系统运行试验结果表明,机器人服务推理方法能够完成智能家庭环境中不同类型的服务推理,从而进一步提高机器人服务的智能性。

关键词: 服务机器人, 本体模型, 智能家庭, 语义网, 服务推理

Abstract:

In order to enhance the ability of robots to provide different types of services, a classification service reasoning method based on semantic web rule language was proposed for service robots in smart home environments. The ontology model of smart home was established by ontology technology, which integrated data from different data sources and eliminated the heterogeneity between devices. The classification of service types were based on the service characteristics of robot service system in smart home. With historical context information, the service rule bases were set up. The reasoning engine could match the real-time context information and service rules to realize the service reasoning of the robot. The experimental results showed that the robot service reasoning method could achieve different types of service reasoning in smart home environments and further improve the intelligence of the robot service.

Key words: service robot, ontology model, smart home, semantic web, service reasoning

中图分类号:

TP242.6

孔令龙,田国会. 智能家庭中一种基于本体的机器人服务认知机制[J]. 山东大学学报 (工学版), 2019, 49(6): 45-54.

Linglong KONG,Guohui TIAN. A robot service recognition mechanism based on ontology in smart home[J]. Journal of Shandong University(Engineering Science), 2019, 49(6): 45-54.

图/表 15

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图2

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图5

表1

图6

图7

表2

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图9

图10

表3

SWRL服务规则"

规则名	规则表示
Rule-1	User(Alan)∧StateUser(sit)∧Location(bedroom)∧Time(t1)∧hasUserState(Alan, sit)∧hasLocation(Alan, bedroom)∧hasTime(sit, t1)→operateOn(drink, coffee)
Rule-2	User(Alan)∧StateUser(sit)∧Location(bedroom)∧Time(t2)∧hasUserState(Alan, sit)∧hasLocation(Alan, bedroom)∧hasTime(sit, t2)→operateOn(drink, water)
Rule-3	User(Bill)∧StateUser(sit)∧Location(bedroom)∧Time(t1)∧hasUserState(Bill, sit)∧hasLocation(Bill, bedroom)∧hasTime(sit, t1)→operateOn(drink, water)
Rule-4	User(Bill)∧StateUser(sit)∧Location(livingroom)∧Time(t2)∧hasUserState(Bill, wake)∧hasLocation(Bill, livingroom)∧hasTime(sit, t2)→operateOn(ON, tv)
Rule-5	User(Bill)∧StateUser(wake)∧Location(bedroom)∧Time(t3)∧hasUserState(Bill, wake)∧hasLocation(Bill, bedroom)∧hasTime(wake, t3)→operateOn(open, window1)
Rule-6	User(Bill)∧StateUser(sleep)∧Location(bedroom)∧Time(t4)∧hasUserState(Bill, sleep)∧hasLocation(Bill, bedroom)∧hasTime(sleep, t4)→operateOn(close, window1)
Rule-7	Items(book1)∧StateItems(on)∧Location(floor)∧Time(t5)∧hasItemsState(book1, on)∧hasLocation(book1, floor)∧hasTime(on, t5)→operateOn(pick, book1)
Rule-8	Items(bread1)∧StateItems(cooled)∧Location(table 1)∧Time(t6)∧hasItemsState(bread1, cooled)∧hasLocation(bread1, table 1)∧hasTime(cooled, t6)→operateOn(heat, bread1)
Rule-9	User(Alan)∧Location(bedroom)∧Environment(temsensor1)∧Time(t7)∧hasLocation(Alan, bedroom)∧hasLocation(aircondition1, bedroom)∧hasTime(temsensor1, t7)∧hasEnvironment(aircondition1, temsensor1)∧value(temsensor1, 28)→operateOn(adjust, aircondition1)∧value(aircondition1, 25)
Rule-10	User(Alan)∧Location(bedroom)∧Environment(temsensor1)∧Time(t8)∧hasLocation(Alan, bedroom)∧hasLocation(aircondition1, bedroom)∧hasTime(temsensor1, t8)∧hasEnvironment(aircondition1, temsensor1)∧value(temsensor1, 16)→operateOn(adjust, aircondition1)∧value(aircondition1, 22)

表3

图11

图12

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序号	条件	服务类型
1	(U₁≠U₂→S_e1≠S_e2) & (U₁=U₂→S_e1=S_e2)	U
2	(S_u1≠S_u2→S_e1≠S_e2) & (S_u1=S_u2→S_e1=S_e2)	S_u
3	(L_u1≠L_u2→S_e1≠S_e2) & (L_u1=L_u2→S_e1=S_e2)	L_u
4	(α≥η→S_e1≠S_e2) & (α < η→S_e1=S_e2)	T_ime
5	(U₁≠U₂, S_u1≠S_u2→S_e1≠S_e2) & (U₁=U₂, S_u1=S_u2→S_e1=S_e2)	U-S_u
6	(U₁≠U₂, L_u1≠L_u2→S_e1≠S_e2) & (U₁=U₂, L_u1=L_u2→S_e1=S_e2)	U-L_u
7	(U₁≠U₂, α≥η→S_e1≠S_e2) & (U₁=U₂, α < η→S_e1=S_e2)	U-T_ime
8	(S_u1≠S_u2, L_u1≠L_u2→S_e1≠S_e2) & (S_u1=S_u2, L_u1=L_u2→S_e1=S_e2)	S_u-L_u
9	(S_u1≠S_u2, α≥η→S_e1≠S_e2) & (S_u1=S_u2, α < η→S_e1=S_e2)	S_u-T_ime
10	(L_u1≠L_u2, α≥η→S_e1≠S_e2) & (L_u1=L_u2, α < η→S_e1=S_e2)	L_u-T_ime
11	(U₁≠U₂, S_u1≠S_u2, L_u1≠L_u2→ S_e1≠S_e2) & (U₁=U₂, S_u₁=S_u2, L_u1=L_u2→S_e1=S_e2)	U-S_u-L_u
12	(U₁≠U₂, S_u1≠S_u2, α≥η→ S_e1≠S_e2) & (U₁=U₂, S_u1=S_u2, α < η→S_e1=S_e2)	U-S_u-T_ime
13	(U₁≠U₂, L_u1≠L_u2, α≥η→ S_e1≠S_e2) & (U₁=U₂, L_u1= L_u2, α < η→S_e1=S_e2)	U-L_u-T_ime
14	(S_u1≠S_u2, L_u1≠L_u2, α≥η→ S_e1≠S_e2) & (S_u1=S_u2, L_u1=L_u2, α < η→S_e1=S_e2)	S_u-L_u-T_ime
15	(U₁≠U₂, S_u1≠S_u2, L_u1≠L_u2, α≥η→S_e1≠S_e2) & (U₁=U₂, S_u1=S_u2, L_u1=L_u2, α < η→S_e1=S_e2)	U-S_u-L_u-T_ime

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